How many grams of NaCl do you have if you have 2.30 x 10 to the 23rd olecules of salt?
Since Avogadro's number is 6.02*10^23, that looks to me like 2.30/6.02 = 0.382 moles of NaCl.
So, multiply 0.382 by the molecular weight of NaCl, which is about 58.5 g/mol