An electron moving through an electric field experiences an acceleration of 6.1 multiplied by 103 m/s2.

(a) Find the electric force acting on the electron.
(b) What is the strength of the electric field?

(a) Force = mass x acceleration

Look up the electron mass

(b) Force = e*E

Solve for the field, E. Use the force from part (a)
e is the electron charge.

(a) Well, if an electron is experiencing an acceleration, that means there must be a force acting on it. So, we can use good old Newton's second law to find the force. F = ma. Just remember, the mass of an electron is about 9.11 x 10^-31 kg, so plug that in along with the acceleration to calculate the force.

(b) Now, to find the strength of the electric field, we need to use the formula F = qE, where F is the force, q is the charge of the electron, and E is the electric field strength. Since we already found the force in part (a), we can divide it by the charge of an electron (about 1.6 x 10^-19 C) to find the electric field strength. And voila, you'll have your answer!

Remember, physics may seem shocking at times, but it always has a positive charge of humor!

To determine the electric force acting on the electron (part a), we can use the equation F = ma, where F is the force, m is the mass, and a is the acceleration.

The mass of an electron is approximately 9.11 x 10^-31 kg.

So, substituting the given values:

F = (9.11 x 10^-31 kg) * (6.1 x 10^3 m/s^2)
F ≈ 5.56 x 10^-27 N

Therefore, the electric force acting on the electron is approximately 5.56 x 10^-27 N.

To find the strength of the electric field (part b), we can use the equation F = qE, where F is the force, q is the charge, and E is the electric field strength.

Since the force acting on the electron has already been determined (5.56 x 10^-27 N) and the charge of an electron is approximately -1.6 x 10^-19 C (coulombs), we can rearrange the equation to solve for E:

E = F / q
E = (5.56 x 10^-27 N) / (-1.6 x 10^-19 C)
E ≈ -3.48 x 10^11 N/C

Therefore, the strength of the electric field is approximately -3.48 x 10^11 N/C. The negative sign indicates that the electric field is directed opposite to the direction of the force acting on the electron.

To find the electric force acting on the electron, you can use Newton's second law, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. The formula is given by:

F = m * a

where F is the force, m is the mass of the object, and a is the acceleration.

(a) Finding the electric force:
In this case, the mass of the electron (m) is a known constant, which is approximately 9.10938356 × 10^−31 kilograms. The acceleration (a) is given as 6.1 × 10^3 m/s^2.

F = (9.10938356 × 10^−31 kg) * (6.1 × 10^3 m/s^2)
F ≈ 5.56 × 10^−27 N

Therefore, the electric force acting on the electron is approximately 5.56 × 10^−27 Newtons.

(b) Finding the strength of the electric field:
The electric force acting on a charged particle is given by the equation:

F = q * E

where F is the force, q is the charge of the particle, and E is the electric field strength.

In this case, we are dealing with an electron, which has a charge of -1.6 × 10^−19 Coulombs. We can rearrange the equation to solve for E:

E = F / q

Substituting the known values:

E = (5.56 × 10^−27 N) / (-1.6 × 10^−19 C)
E ≈ -3.475 × 10^11 N/C

Since electric field is a vector quantity, the negative sign indicates that the electric field is directed in the opposite direction of the acceleration experienced by the electron.

Therefore, the strength of the electric field is approximately 3.475 × 10^11 N/C (directed opposite to the direction of electron's acceleration).