Trig.
posted by Tara .
Can you please review this to see if I did this right?
2cos^2x+3cosx=0
sq. root of (cos^2x)+(cosx)=sq. root of (3/2)
2cos=(sq. root of 3 times sq. root of 2)/2)) times 2/1
cos=(2 times sq. root of 3 times sq. root of two)/2))
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