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A supersoaker water pistol can hold up to 4 litres of water. If each shot uses 11/12 of amount of water of its previous shot, the amount of water fired by a fully loaded supersoaker's first shot is?


why is the answer 333mL?

  • math -

    This is an infinite geometric series and the sum of the series is one liter

    Sum = 1000 mL = g/(1-r) where r=11/12 and g is the first term, what we want.
    1000 = g/(1/12)
    g = 1000/12 = 83.33 mL

  • math -

    oh, sorry, 4 liters not one
    times 4
    83.33*4 = 333.3333.... mL

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