Trains a and b are traveling in the same direction on parallel tracks;Train a is traveling 40mph and train b is traveling 50mph. Train A passes a station at 8:15 am. If train b passes the same station at 8:27 am what time will train b catch up to train a?
I know this is a distant rate a time question but cannot seem to write out the correct formula and arrive at a correct answer.
well... im not exactly a teacher but, if u subtract 8:15 and 8:27 you will find the time difference
To solve this problem, you need to use the formula:
time = distance / rate
However, in this case, we don't know the distance between the station and the point where train B catches up to train A. But we can determine it using the information given.
The time difference between Train A passing the station (8:15 am) and Train B passing the same station (8:27 am) is 12 minutes (or 12/60 = 0.2 hours).
During this time difference, Train A would have traveled a distance equal to its rate multiplied by the time difference:
Distance covered by Train A = 40 mph × 0.2 hours = 8 miles
Now, the problem becomes finding the time it takes for Train B to cover 8 miles while traveling at a speed of 50 mph.
Using the formula time = distance / rate, we can calculate:
Time for Train B to cover 8 miles = 8 miles / 50 mph = 0.16 hours
To determine the actual time, we need to add this time to the time Train B passed the station (8:27 am):
0.16 hours × 60 minutes/hour = 9.6 minutes = 10 minutes (approximately)
Therefore, Train B will catch up to Train A at 8:27 am + 10 minutes = 8:37 am.
So, Train B will catch up to Train A at 8:37 am.