# Trig

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Solve: 3tan^2x-1=0. I got +/- (the sq. root of 3)/3 which is correct according to my study guide. However, I don't know how to use the unit circle to find this. The copy of the unit circle which I have does not have tangent values listed, only sine and cosine. I've tried googling unit circle with no avail. Would you be able to share with me what the tan values are for pi/6, pi/4 and pi/3? Thanks so much.

• Trig -

tan(x) = sin(x) / cos(x)

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