I don't know how to go about solving this problem: There were 93 students going to camp. After equal groups of fewer than 10 students were formed for hiking. 2 students were left over . How many equal groups were formed?
Thanks!
You'll need to try it out with different numbers.
93 ÷ 9 =
93 ÷ 8 =
93 ÷ 7 =
Etc.
the answer is 9
9 groups does not leave a remainder of 2.
Also 9 groups would have to have 10 persons in each group, but the instructions indicate "fewer than ten."
As Writeacher indicates, you need to try it out with different numbers to find which one gives a remainder of 2.
93/9 = 10 groups but remainder of 3
93/8 = ?
93/7 = ?
And so on.
I hope this helps a little more.
im in 4th grade and i think it might be 81 i might have done it wrong but at least i tried...
50X1=50
To solve this problem, you need to find the number of equal groups that were formed after dividing the total number of students by the number of students in each group.
First, subtract the number of students left over (2) from the total number of students (93). This will give you the total number of students that evenly formed groups can be made from.
93 - 2 = 91
Now, you need to divide this total number of students (91) by the maximum number of students in each group (which is less than 10).
Since the problem states that the groups have to be formed with fewer than 10 students, you can choose any number less than 10 for your division. Let's choose 9.
So, divide 91 by 9:
91 ÷ 9 = 10 remainder 1
This means that you can form 10 equal groups of 9 students, with 1 student left over.
Therefore, the answer to the problem is that 10 equal groups were formed.