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Three towns p, q and r are such that the distance between p and q is 50km and the distance between p and r is 90km. If the bearing of q from p is 075 and the bearing of r from p is 310, find the
(a)distance between q and r
(b)bearing of r from q

  • bearing -

    answered above

  • bearing -

    A)distance qr=
    |ar|^2=q^2+r^2-2pqcosP
    =90^2+50^2-2*50*90cos125
    =8100+2500-9000cos125
    =10600+5162.1879
    =root of 10600+5162.1879
    qr=130
    b)The bearing of r from q=
    =q/sinQ=p/sinP
    =90/sinQ=130/sin125
    =130sinQ=90sin125
    Q(sin)=73.72/130
    Q=34.6
    Then the bearing of r from q=360-34.6
    =325.4

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