Simplifying fractions. I can get from this:
4b^2-5b-6
__________
8b^2 + 6b
To this:
(4b+3)(b-2)
___________
2b(4b+3b)
Not sure from there.
Try the distrubutive property, or cancelling
i just don't know if i have to take that another step or not. my teacher said that if in the 2nd step we could not canel anything out that we did something wrong, i am unable to cancel anything out but i can't find another way to set up the problem.
To simplify the fraction (4b^2 - 5b - 6) / (8b^2 + 6b), you have correctly factored the numerator as (4b+3)(b-2).
Now, let's simplify the denominator. The denominator can be factored as 2b(4b + 3b).
Simplifying further, we can combine like terms in the denominator to get 2b(7b).
So now, the fraction is (4b+3)(b-2) / 2b(7b).
However, we can still simplify it further.
Notice that both the numerator and the denominator have a factor of (4b+3). We can cancel this common factor to simplify the fraction.
Cancelling out (4b+3) from both the numerator and denominator, we get:
(4b+3)(b-2) / 2b(7b) = (b-2) / 2b(7b).
Finally, the simplified fraction is (b-2) / 2b(7b).