An occupant of a car has a chance of surviving a crash if the deceleration during the crash is not more than 30 g. Calculate the force on a 70 kg person deceleerating at the same rate.

Force equals mass times acceleration. If you multiply them together, you get the force in Newtons.

acceleration = 30g = 30 * 9.8 m/s^2 = 294 m/s^2

294 x 70 = ___ N

One Newton is about a quarter pound of force.

Here's another way to look at it: The decelerating force will be 30 times the person's weight.

drwls is exactly right

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Well, it seems your car is going to give you a real "g"-force experience! Let's calculate the force, shall we?

To find the force, we need to find the deceleration first. Assuming one "g" is equal to 9.8 m/s², we can determine that a deceleration of 30 g is equivalent to 30 × 9.8 m/s².

So, the deceleration is approximately 294 m/s².

Now let's find the force using Newton's second law, which states that force (F) is equal to mass (m) times acceleration (a).

F = m × a

Plugging in the values, we get:

F = 70 kg × 294 m/s²

Calculating that, we find:

F ≈ 20,580 N (Newtons)

So, according to my calculations, you would experience a force of approximately 20,580 Newtons! Hang on tight, my friend!

To calculate the force on the person, we can use Newton's second law of motion which states that force (F) is equal to mass (m) multiplied by acceleration (a):

F = m * a

In this case, the mass of the person is given as 70 kg. But we need to convert the deceleration rate from "g" to meters per second squared (m/s^2) since the unit of force is Newtons (N).

1 g is approximately equal to 9.8 m/s^2, so we can convert the deceleration rate of 30 g to m/s^2 by multiplying it by 9.8:

30 g * 9.8 m/s^2 = 294 m/s^2

Now we can calculate the force:

F = 70 kg * 294 m/s^2

F = 20,580 N

Therefore, the force on a 70 kg person decelerating at a rate of 30 g is approximately 20,580 Newtons.

20,580