I am les than a 100. The sum of my digit is 8. If you divide me by two, I am even number. My tens digit and my ones digit are thye same?
I am les than a 100 --- so it has to be a 2 digit number
My tens digit and my ones digit are thye same --- so it must be 11, 22, 33, .. 99
The sum of my digit is 8 -- looks like 44 is it !!
If you divide me by two, I am even number --- 44/2 = 22
Yup, it is 44
To find the number that meets these criteria, we can start by considering that the sum of the digits is 8. We also know that the tens digit and ones digit are the same.
Let's analyze the possible two-digit numbers that fit these criteria.
If we start with the number 19, which is less than 100 and has a digit sum of 8, we can divide it by two resulting in 19/2 = 9.5. As this is not an even number, we can exclude 19.
Next, we consider the number 28. Dividing 28 by two results in 28/2 = 14, which is an even number, satisfying one of the conditions. Additionally, 28 has a digit sum of 2 + 8 = 10, meaning that it fails the condition that the sum of its digits is 8.
Moving on, we examine the number 37. Dividing 37 by two, we get 37/2 = 18.5, which is not an even number. Hence, we can exclude 37.
Finally, we check the number 46. Dividing 46 by two gives us 46/2 = 23, which is an odd number, so it does not fit the criteria.
Therefore, we have checked all possible numbers and found that there is no two-digit number that satisfies the given conditions (less than 100, digit sum of 8, divisible by 2 to get an even number, and tens digit being the same as the ones digit).