A forward force of 8X102 Newtons is applied to a 1.9x103 kg car. If the friction force on the car is 6x102 Newtons what is the acceleration of the car in units of m/s2?
To find the acceleration of the car, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, the net force is the forward force applied to the car minus the friction force acting against it.
Given:
Forward force (F) = 8x10^2 Newtons
Friction force (Ff) = 6x10^2 Newtons
Mass of the car (m) = 1.9x10^3 kg
Using Newton's second law, we can set up the following equation:
F - Ff = ma
Substituting the given values:
8x10^2 N - 6x10^2 N = (1.9x10^3 kg) x a
Simplifying:
2x10^2 N = (1.9x10^3 kg) x a
To isolate the acceleration (a), divide both sides of the equation by the mass of the car:
a = (2x10^2 N) / (1.9x10^3 kg)
Now, simplify the expression:
a = 0.105 m/s^2
Therefore, the acceleration of the car is 0.105 m/s^2.