Algebra
posted by Kimba .
(2x^3)(14x^2)+12x=0
x=?

First, factor out the common 2x.
This leaves you with
2x[x^2 6x +6) = 0
x=0 is one solution. The others are the two roots of
x^2 6x +6 = 0,
which are not integers. You can compute them with the quadratic equation
x = [6 +/ sqrt(12)]/2 = 3 +/ sqrt3
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