Find the product.
(n^3)^3 · (n^4)^5 = n____
(n^3)^3 · (n^4)^5 = n*9 * n^20 = n^29
Here is what you need to remember:
Exponents multiply when you raise an exponential to a power
[as in (n^3)^3 = n^9],
and add when you multiply two exponential terms together
(as in n^9 * n^20 = n^29).
To find the product of (n^3)^3 and (n^4)^5, we can simplify each expression separately first and then multiply the results.
Let's start with (n^3)^3. To simplify this expression, we need to raise n^3 to the power of 3.
(n^3)^3 = n^(3 * 3) = n^9
Next, let's simplify (n^4)^5. We need to raise n^4 to the power of 5.
(n^4)^5 = n^(4 * 5) = n^20
Now, we have n^9 multiplied by n^20. To multiply two terms with the same base, we add their exponents.
n^9 * n^20 = n^(9 + 20) = n^29
Therefore, the product of (n^3)^3 and (n^4)^5 is n^29.