Question

Janes aquarium holds goldfish, turtles, and snails. there are 16 legs, 10 shells, and 36 eyes. how many creatures of each type are in the aquarium? (Hint: snails have one leg and one shell)

Please please help me. I figured out there are 12 pets(I think) but i can not find out anything else

Answer 1

36/2 = 18

Since each creature has 2 eyes each, there must be 18 pets.

10 of these pets have shells; so there must be 10 snails and turtles combined, leaving:

8 goldfish

2 turtles (2 shells and 8 legs)

8 snails (8 shells and 8 legs)

Answer 2

THANK YOU SO MUCH!!

Answer 3

You're very welcome.

Answer 4

Thank u!!!!!!

Answer 5

Thank you for solving that mathematical equation Ms Sue.

Answer 6

yes

Answer 7

[AI-generated answer — Explain Bot]

To solve this problem, let's assign variables for each type of creature in the aquarium.

Let's say:
- Goldfish = G
- Turtles = T
- Snails = S

Now, we can use the given information to create equations:

1) Number of legs:
Goldfish have 0 legs.
Turtles have 4 legs.
Snails have 1 leg.

So, based on the given information, we can write the equation:
0G + 4T + 1S = 16 (equation 1)

2) Number of shells:
Goldfish have 0 shells.
Turtles have 1 shell.
Snails have 1 shell.

So, we can write another equation:
0G + 1T + 1S = 10 (equation 2)

3) Number of eyes:
Goldfish have 2 eyes.
Turtles have 2 eyes.
Snails have 2 eyes.

We can write the third equation as:
2G + 2T + 2S = 36 (equation 3)

Now, we have a system of three equations with three variables (G, T, and S).

From here, we can use various methods to solve the system of equations, such as substitution or elimination.

Let's use the elimination method to solve this system:

Multiplying equation 1 by 2 gives us:
0G + 8T + 2S = 32 (equation 4)

Now, we can subtract equation 4 from equation 3:
(2G + 2T + 2S) - (0G + 8T + 2S) = 36 - 32
2G - 6T = 4 (equation 5)

Next, we'll multiply equation 2 by 2:
0G + 2T + 2S = 20 (equation 6)

We can subtract equation 6 from equation 5:
(2G - 6T) - (0G + 2T + 2S) = 4 - 20
2G - 8T - 2S = -16 (equation 7)

Now, adding equation 4 and equation 7:
(0G + 8T + 2S) + (2G - 8T - 2S) = 32 - 16
2G = 16
G = 16/2
G = 8

Substituting the value of G into equation 4, we get:
0(8) + 8T + 2S = 32
8T + 2S = 32
4T + S = 16 (equation 8)

Now, looking at equations 7 and 8, we can use substitution or elimination method again. However, since the coefficients are quite small, let's try substituting values.

Let's solve equation 8 for S:
S = 16 - 4T (equation 9)

Substituting equation 9 into equation 7:
2G - 8T - 2(16 - 4T) = -16
2G - 8T - 32 + 8T = -16
2G - 32 = -16
2G = -16 + 32
2G = 16
G = 16/2
G = 8

Substituting the value of G into equation 8:
4T + S = 16
4T + (16 - 4T) = 16
4T + 16 - 4T = 16
16 = 16

This equation is true, but it doesn't provide us with any new information. Therefore, we have reached a point where any value of T and S that satisfies the original equations will work.

In conclusion, there are 8 goldfish, and the number of turtles and snails can vary as long as they satisfy the original equations. So, we cannot determine the exact number of turtles and snails in the aquarium.