A bike travels at a constant speed of 4.0 m/s for 5.0 s. How far does it go?
GIVEN:
V = 4.0 m/s
t = 5.0 s
Would you use this equation?
D= Vit + 1/2 at^2
Yes, the equation
D= Vit + 1/2 at^2
is appropriate with or without acceleration.
Constant speed means that the acceleration (a) is zero, so the second term disappears to degenerate into the more familiar equation:
Distance = Speed * Time.
20
bbbb
No, the equation D = Vit + 1/2 at^2 is for calculating the displacement of an object that is undergoing constant acceleration. In this case, the bike is traveling at a constant speed, which means it has no acceleration.
To find the distance the bike travels, you can simply multiply its constant speed by the time it travels:
Distance = Speed x Time
In this scenario, the bike's speed is 4.0 m/s, and the time is 5.0 s. Plugging these values into the equation:
Distance = 4.0 m/s * 5.0 s = 20.0 m
Therefore, the bike travels a distance of 20.0 meters.