Solve for x

2^x=8^x-3

Do you mean 8^(x-3) or (8^x) -3?


What you wrote could be interpreted either way. They are not the same.

If you meant 2^x = 8^(x-3), then solve as follows:

2^x = (2^3)^(x-3) = 2^(3x -9)
The exponents of 2 on either side must be the same.
x = 3x -9
2x = 9
x = 9/2