(2,4) and (6,6) what is the equation of the line y=
Marth actually told you a way to do it
slope = m = (6-4)/(6-2) = 2/4 = 1/2
so
y - y1 = m(x - x1)
y - 4 = (1/2)(x-2)
2y - 8 = x - 2
2y = x + 6
Find the slope, m = (y2-y1)/(x2-x1).
Then use the equation y - y1 = m(x - x1) with either point to find the equation of the line.
so what is y= then?
it also says im supposed tp find an equation of the line containing the given pair of points?
a drop from 100 to 50 is 50. a rise 50 to 100. will the percent of decrease and the percent of increase be the same.
To find the equation of a line passing through two given points, we can use the point-slope form of a linear equation.
Given the two points (2,4) and (6,6), we can calculate the slope of the line using the slope formula:
slope (m) = (change in y) / (change in x)
Let's calculate the slope first:
(change in y) = 6 - 4 = 2
(change in x) = 6 - 2 = 4
slope (m) = 2 / 4 = 1/2
Now that we have the slope (m), we can use it along with one of the given points to write the equation of the line in point-slope form:
y - y₁ = m(x - x₁)
Using the point (2,4) we can substitute the values into the equation:
y - 4 = (1/2)(x - 2)
Simplifying the equation, we get:
y - 4 = (1/2)x - 1
Adding 4 to both sides, we have:
y = (1/2)x + 3
Therefore, the equation of the line passing through the points (2,4) and (6,6) is:
y = (1/2)x + 3