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Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 miles per hour and train B is traveling at 80 miles per hour. Train A passes a station at 5:15 A.M. IF train B passes the same station at 5:27A.M., at what time will train B catch up to train A?

  • algebra -

    At 5:27 am, train B is behind train A by
    (27-15)/60*60 h*mph
    = 12 mi
    Train B's speed exceeds that of train A by
    (80-60)=20 mph.
    Can you take it from here?

  • algebra -

    A travels for time t
    B travels for time (t - 12 minutes )
    A goes 60 mph = 1 mile/minute
    B goes 80 mph = 4/3 mile/minute
    distance is the same
    so
    1 t = (4/3)(t-12)
    3 t = 4 t - 48
    t = 48 minutes
    5:15 + 48 minutes = 5:63 which is 6:03

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