I have a algebra question not to good at this? here goes..

the fuction w (d)=0.112d approximates the amount in centimetres of water that results from D cm of snow melting. find the amount of water that results from snow melting depths of.
19cm
38cm
95cm

The amount of water from 19cm of snow melting = w(19) = 0.112*19

The amount of water from 38cm of snow melting = w(38)

so then it would be w(19)=0.112*19

and
w (38)=0.112*38
and w (95)=0.112*95

Yes.

ok thank you

To find the amount of water that results from snow melting depths of 19 cm, 38 cm, and 95 cm using the given function w(d) = 0.112d, you simply need to substitute the snow depth values into the function and calculate the corresponding water amounts.

For the first case, with a snow melting depth of 19 cm, you can plug in d = 19 into the function:
w(19) = 0.112 * 19 = 2.128 cm

So, 19 cm of snow melting would result in approximately 2.128 cm of water.

For the second case, with a snow melting depth of 38 cm:
w(38) = 0.112 * 38 = 4.256 cm

Hence, 38 cm of snow melting would result in approximately 4.256 cm of water.

For the third case, with a snow melting depth of 95 cm:
w(95) = 0.112 * 95 = 10.64 cm

Therefore, 95 cm of snow melting would result in approximately 10.64 cm of water.

By substituting the snow depths into the function and performing the calculations, you can determine the amount of water that results from specific snow melting depths using the given approximation formula.