the perimeter of a rectangle is 136 m. The length is 2m more than twice the width. Find the dimensions

what is the length? ____m?
what is the width ____m?

Let w = width

2w + (2w + 2) = 136
4w + 2 = 136
4w = 132
w = 33

To find the dimensions of the rectangle, we can use the given information about the perimeter and the relationship between the length and width.

Let's denote the width of the rectangle as "w" and the length as "l".

From the given information, we know that the perimeter of the rectangle is 136m. The formula for the perimeter of a rectangle is P = 2l + 2w, where P is the perimeter, l is the length, and w is the width.

Given that P = 136m, we can substitute this into the formula:
136 = 2l + 2w

We are also given that the length is 2m more than twice the width. In mathematical terms, we can express this as:
l = 2w + 2

Now, we can substitute the value of "l" from the second equation into the first equation:
136 = 2(2w + 2) + 2w

Simplifying the equation:
136 = 4w + 4 + 2w
136 = 6w + 4

Next, we isolate "w" by subtracting 4 from both sides of the equation:
136 - 4 = 6w
132 = 6w

Dividing both sides of the equation by 6:
22 = w

Therefore, the width of the rectangle is 22m.

To find the length, we'll substitute the value of "w" into the equation for the length:
l = 2w + 2
l = 2(22) + 2
l = 44 + 2
l = 46

Therefore, the length of the rectangle is 46m.

In summary, the dimensions of the rectangle are as follows:
Length = 46m
Width = 22m