M[4,3_1,2]-M[1,1_1,0]+M[1,1_1,4]
perform the indicated operations where possible
What is the meaning of the 'underscore' _ ?
Are these matrices ?
Why, if they are different matrices, do they have the same name M ?
To add/subtract same-size matrices simply add/subtract the corresponding elements.
[4,3_1,2]-[1,1_1,0]+[1,1_1,4]
yes this is a matrice. when it through the m in there I thought it was right
To perform the indicated operations, we need to subtract the second matrix from the first matrix and then add the third matrix to the result.
Let's break down the problem step by step:
Step 1: Subtract the second matrix from the first matrix.
M[4,3_1,2] - M[1,1_1,0]
When subtracting matrices, we subtract the corresponding elements in each position.
The first element in the first row of the first matrix (4) minus the first element in the first row of the second matrix (1) gives us 4 - 1 = 3.
The second element in the first row of the first matrix (3) minus the second element in the first row of the second matrix (1) gives us 3 - 1 = 2.
The first element in the second row of the first matrix (1) minus the first element in the second row of the second matrix (1) gives us 1 - 1 = 0.
The second element in the second row of the first matrix (2) minus the second element in the second row of the second matrix (0) gives us 2 - 0 = 2.
Therefore, the result of the subtraction is:
M[3,2_0,2]
Step 2: Add the third matrix to the result from Step 1.
M[3,2_0,2] + M[1,1_1,4]
When adding matrices, we add the corresponding elements in each position.
The first element in the first row of the result from Step 1 (3) plus the first element in the first row of the third matrix (1) gives us 3 + 1 = 4.
The second element in the first row of the result from Step 1 (2) plus the second element in the first row of the third matrix (1) gives us 2 + 1 = 3.
The first element in the second row of the result from Step 1 (0) plus the first element in the second row of the third matrix (1) gives us 0 + 1 = 1.
The second element in the second row of the result from Step 1 (2) plus the second element in the second row of the third matrix (4) gives us 2 + 4 = 6.
Therefore, the final result is:
M[4,3_1,6]
So, M[4,3_1,2]-M[1,1_1,0]+M[1,1_1,4] = M[4,3_1,6]