The Everton College store paid $1926 for an order of 50 calculators. The store paid $10 for each scientific calculator. the others, all graphing calculators, cost the store $56 each. How many of each type of calculator was ordered? scientific? graphing?
Let G=number of graphing calculators, then
$10*(50-G)+$56*G = $1926
Solve for G and substitute back in formula to check answer.
To determine the number of each type of calculator that was ordered, we can set up a system of equations based on the information given.
Let's denote the number of scientific calculators as 's' and the number of graphing calculators as 'g'.
From the given information, we know that the store paid $1926 for the order. We can express this as an equation:
10s + 56g = 1926
Additionally, we are told that the store ordered a total of 50 calculators. So we have:
s + g = 50
Now we can solve this system of equations to find the values of 's' and 'g'.
One way to solve this system is by substitution. We start by solving one equation for one variable and then substituting it into the other equation.
From the second equation, we can solve for 's':
s = 50 - g
Now we substitute this value of 's' into the first equation:
10(50 - g) + 56g = 1926
Expanding and simplifying:
500 - 10g + 56g = 1926
46g = 1926 - 500
46g = 1426
Dividing both sides by 46:
g = 1426 / 46
g ≈ 31
Now we have the value of 'g', which represents the number of graphing calculators. We can substitute this value back into the second equation to find the value of 's':
s + 31 = 50
s = 50 - 31
s = 19
Therefore, the number of scientific calculators ordered is 19, and the number of graphing calculators ordered is 31.