How much work is done by a crane that lowers 1000 N of material at a distance of 150 m?

two tuning forks are struck at the same time one turning fork has a frequency of 20 Hz the second turning fork has a frequency off 226 Hz how may beats will result

To calculate the amount of work done by the crane, you need to know the formula for work:

Work = Force x Distance x cos(theta)

Where:
- Work is measured in joules (J)
- Force is measured in newtons (N)
- Distance is measured in meters (m)
- theta represents the angle between the force and the direction of motion (cos(theta) accounts for the angle)

In this case, the force exerted by the crane is 1000 N, and the distance over which the material is lowered is 150 m. Since the vertical downward direction is considered the positive direction, the angle between the force and the direction of motion is 0 degrees. Therefore, cos(0) = 1.

Plugging these values into the formula:

Work = 1000 N x 150 m x cos(0)

Since cos(0) equals 1:

Work = 1000 N x 150 m x 1

Work = 150,000 J

Therefore, the crane does 150,000 joules (J) of work while lowering the material.