posted by amelia .
I'm not sure how to do this question
7. The growth of bacteria in culture can be described by the equation
N1 = N0e'
where N is the number of bactena at any time t, No is the initial number of bacteria, and k
is a constant. The time taken for growth to double the number of bacteria of a particular
strain (the 'doubling time') was 30 mm. A culture was started with 200 bacteria of this
Determine the followmg (giving appropnate units in each case)
(a) the value of k for this strain (2]
(b) the rate of increase m bacterial number when the number in the colony
was 2000 131
(c) the minimum number of bacteria in this culture (1]
for a i calculated k =0.023 or (ln 2)/30
for c i think it would be at t = 0
Nt = No.e^(k0)
Nt = No.e^0
Nt = No.1
Nt = No = 200
i don't know how to do b and im not sure if im right with a and c please help
I cannot follow what you are doing. Your original equation
N1 = N0e'
is wrong, and you quote a doubling time im millimeters.
To obtain help, you need to be more careful posting your questions.
First of all your opening equation should have been
N1 = N0 e^(kt), where t is in minutes.
Does 30 mm mean "30 minutes" ? (I assumed that)
I did get the same value of k.
so your equation is
N = 200 e^(.023105t)
the rate of increase is the derivative of your function, so
dN/dt = 200(.023105) e^(.023105t)
So we now have to find the value of t when N = 2000131
2000131 = 200 e^(.023105t)
for that I got t = 398.6 minutes
(you better check my arithmetic here)
Now sub that t value back into our derivative to find the rate of change at that time.
c) is a strange question. Since it is exponential growth, the minimum value would be at the start, namely 200
sorry it was a copy and paste job should checked it thanks for the help