# Chemistry

posted by .

Find the [H3O+] in a solution having [OH-] = 8.8x10^-2 M

[H3O+]x[OH-]=1x10^-14
[H3O+]x[8.8x10^-2]=1x10^-14

i am almost sure i am right up to here but i don't know what to do next and i don't have a scientific calculator.. please help!!

• Chemistry -

Good lord. YOu will not pass Chemistry, nor learn it,without a scientific calculator. Just how do you plan on getting logarithms?

1E-14 / 8.8E-2

## Similar Questions

1. ### Chemistry

Calculate the end point pH, when 25 mL of 0.01 mol/L HCl solution reacts exactly with 25 mL of 0.1 mol/L NH4OH solution. NH3 Kb = 1.8 x 10^-5 This will be the pH of NH4Cl solution. NH4+ + HOH ==> NH3 + H3O^+ Ka = Kw/Kb = (NH3)(H3O^+)/(NH4^+). …

Find the pH of a mixture of .150 M HF(aq) solution and 0.100 M HClO2(aq) HF + H2O <--> F- + H3O+ Ka= 3.5*10^-4 So I will show my attempt below... [HF] [F-] [H3O+] I .150 0 0 C -x +x +x E .15-x x x Ka= [F-][H3O+]/[HF] 3.5*10^-4= …
3. ### Help Chemistry

Can you please tell me if these are right?
4. ### Chem

Please tell me if these are right! What are the [H3O+] and [OH-] for a solution with the following pH values?
5. ### chemistry

7). The pH of a solution is 2.89. What is the [H3O+]?

What is the [H3O+] for a neutral solution at 50 degrees celsius?
7. ### Chemistry(Please respond, thank you)

What is the [H3O+] for a neutral solution at 50 degrees celsius?
8. ### Chemistry

4. 5.6 x 10-6 mol of A and 5 x 10-5 mol of B are mixed in a 200 mL flask. The system is represented by the equation: 2A + B --> 3C I 2.8x10-5 M 2.5x10-4 0 C -2x -x +3x E 2.8x10-5-2x 2.5x10-4-x 3x10-5 B = 2.5x10-4-x = 2.4x10-4 x …
9. ### Chemistry

Compare the g/L solubility of CaCO3 in pure water, a H3O+ (aq) solution with a PH of 3.00 and a H30+(aq) solution with a pH of 1.00. Ksp for CaCO3 is 3.36 x 10^-9 CaCO3 (s) + H3O (aq) = Ca (aq) + HCO3 (aq) + H2O (l) (equilibrium equation) …
10. ### Chemistry

Calculate the pH of a solution in which a. [H3O+] = 7.8 x 10-7 M pH = b. [H3O+] = 5.1 x 10-6 M pH = c. [H3O+] = 6.1 x 10-5 M pH = d. [H3O+] = 9.3 x 10-4 M pH = I get 8.1 9.5 9.1 6.7 but its wrong please someone help!

More Similar Questions