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waht is the slope of the normal line to y^2 = x/2 at P(1/8,1/4)??

  • math -

    Janice, Nadine, Elmo, Keisha and Amber, you're probably working together one way or another. So you can also help each other.

    As before, use implicit differentiation to get y':
    2yy'=(1/2)
    y'=(1/2)/(2y)
    The slope of the normal is given by
    m=-1/y'=-4y
    So the line for the normal is
    L1: (y-y1)=m(x-x1)

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