Math
posted by Anonymous .
Find the area of a triangle with a base of 3 5/8 in. and a height of 2 1/2 in.
A)4 15/32 in 2 (sq)
B)8 1/16 in 2 (sq)
C)4 17/32 in 2 (sq)
D)8 17/32 in 2 (sq)
Help!! I am so confused.

Area of triangle = (1/2)base*height
here we need to convert the mixed numbers (i.e. sum of number and fractions) to improper fractions (numerator is greater than the denominator) to facilitate the eventual multiplication:
base = 3 5/8 in. = (8*3+5)/8" = 29/8"
height = 2 1/2 in. =(2*2+1)/2" = 5/2"
Now calculate the area
A = (1/2)*(29/8)*(5/2)
=145/32 sq.in.
Convert the improper fraction into a mixed number and make your choice of the answers.
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