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If a ball is thrown off a 17.9m roof with the velocity of 23.9m/s and it takes 1.91sec to reach the ground, What is the horizontal displacement and the Velocity right before it hits the ground?

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    They don't tell you the angle (measured above horizontal) that the ball was thrown, but you can figure it out.

    For a ball thrown horizontally, the distance fallen (vertically) is
    Y = (g/2) t^2 = 17.9 m

    Since that is also the height of the building, it WAS thrown horizontally. The horizontal velcoity component remains 23.9 m/s

    Just multiply the initial velocity by the time of flight, to get the horizontal displacement.

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