algebra
posted by Mike .
solve using the multiplication principle:
7x > 1/15

Solve: 4x < .8
Solution: Using the Multiplication Principle, multiply both
sides of the inequality by .25. Then reverse the
signs.
.25(4x) > .25(.8)
x > .2 
Wow you lost me. So how would that work with a fraction, do you still do it by .25?

If 3X  1 = 11, what is the value of X^2 + X?

7x > 1/15
divide both sides by 7, remembering to reverse the inequality sign
x < 1/105
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