1.m=-2,(2,6)

To find the equation of a line when given the slope and a point, you can use the point-slope form of a linear equation. This form is written as:

y - y1 = m(x - x1)

Where m is the slope, (x1, y1) is a point on the line, and (x, y) represents any other point on the line.

In this case, the slope (m) is given as -2, and the point (2, 6) is given. We can substitute these values into the point-slope form to find the equation:

y - 6 = -2(x - 2)

Simplifying the equation:

y - 6 = -2x + 4

Now, we can rewrite the equation in slope-intercept form (y = mx + b) by isolating y:

y = -2x + 10

Therefore, the equation of the line with a slope of -2 and passing through the point (2, 6) is y = -2x + 10.