Calculus
posted by Nancy .
the grand canyon is 1600 meters deep at its deeoest point. a rock is dropped fromthe rim above this point. Express the height of the rock as a function T in seconds. how long will it take the rock to hit the canyon floor?
H= 16001/2t^2
thats what i got as a function is that correct cause it doesnt work to get the final answer on how long it would take the rock to hit the floor.

You forgot the acceleration of gravity before the t^2
H = Ho  (1/2)gt^2 = 1600 (9.8/2)t^2
Set that equal to 0 and solve for t.