Find the slope of the line containing the points (-9, 1/2) and (-5, 1/2)
Using the point slope formula
m=(y2-y1)/(x2-x1)
m=([1/2]-[1/2])/([-5]-[-9])
m=0/4
m=0
In other words, this is a horizontel line, with a slope of 0
m=rise/run
Thank you ALan. I will copy the formual to use for another time!
To find the slope of the line containing the points (-9, 1/2) and (-5, 1/2), you can use the formula for slope:
slope (m) = (y2 - y1) / (x2 - x1)
Let's calculate it step by step:
1. Identify the coordinates of the two points:
Point 1: (-9, 1/2) -> x1 = -9, y1 = 1/2
Point 2: (-5, 1/2) -> x2 = -5, y2 = 1/2
2. Plug the coordinates into the slope formula:
slope (m) = (y2 - y1) / (x2 - x1)
= (1/2 - 1/2) / (-5 - (-9))
3. Simplify the expression:
slope (m) = (0) / (-5 + 9)
= 0 / 4
Since any number divided by zero is undefined, the slope of this line is undefined or "no slope." This means the line is a horizontal line, parallel to the x-axis and does not change in the y-direction.