A bolt is to be tightened with a torque of 8.0 N*m. If you have a wrench that is 0.35 m long, what is the least amount of force you must exert?

the equation for this problem is
t=Fr sinbeta, but the sin is not given What am I suppose to do?

force*arm=torque

Now on the angle, don't we move wrenches at 90 degrees?

When dealing with torque problems, the equation you mentioned, t = Frsinβ, is commonly used. However, to solve this equation, you'll need to know the angle, β, between the force, F, and the lever arm, r.

In this particular problem, since the angle, β, is not given, we can assume that the force applied is perpendicular to the lever arm. This means that sinβ = 1, as sin(90 degrees) = 1.

Now, you can re-write the equation as t = Frsinβ = Fr. Since sinβ = 1, the equation becomes t = Fr.

To find the force, F, you can rearrange the equation as F = t / r.

Given a torque of 8.0 N*m and a wrench length of 0.35 m, you can calculate the least amount of force you must exert by dividing the torque by the lever arm:

F = 8.0 N*m / 0.35 m = 22.86 N

Therefore, the least amount of force you need to exert is approximately 22.86 Newtons.

In this problem, the torque is given as 8.0 N*m and the length of the wrench is 0.35 m. The equation you mentioned, t = Fr sin(beta), relates torque (t), force (F), length of the wrench (r), and the angle between the force and the wrench (beta). However, in this case, the value of sin(beta) is not given.

To find the least amount of force you must exert, you need to assume a value for sin(beta). In this case, since sin(beta) is not given, you can assume it to be 1, which is the maximum value for sin(beta). This means you assume that the force is applied at a 90-degree angle to the wrench.

Using the equation t = Fr sin(beta), you can rearrange it to solve for force (F):

F = t / (r * sin(beta))

Substituting the given values, we get:

F = 8.0 N*m / (0.35 m * 1) = 22.86 N

So, the least amount of force you must exert is approximately 22.86 Newtons.