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solve algebriaclly the equation y=2sin2x+1 for 0<_x_<180. when solved find the x coordinates of the roots.

I am assuming you are trying to solve
2sin2x+1 = 0
sin 2x = -1/2
(angle in standard position is 30º)
the sine is negative in quadrants III and IV
so x = 180+30 = 210
or x = 360-x30 = 330

Btw, don't shout!

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When you type in all-caps, two things happen:
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• Correction -

my last couple of lines should have been
so 2x = 180+30 = 210
or 2x = 360-x30 = 330

so x = 105 or x = 165

since the period of sin 2x is 180º
two other solutions are 285º and 345º

check: 2sin(2x345) + 1 = 0

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