posted by Janet .
At the first tri-city meeting, there are 8 people from town A, 7 people from town B, and 5 people from town C. If a council consisting of 5 people is randomly selected, find the probability that 3 are from town A and 2 are from town B.
Without restrictions, number of councils is
C(20,5) or 15504
I will assume you want exactly 3 from A and 2 from B, so that number is C(8,3)xC(7,2) or 1176
so prob(of stated event) = 1176/15504
= 49/646 or .07585