Triangle ABC has vertices A = (0,6) B = (-2,3), and C = (2,1). Find the coordinates of its vertices if it is translated by the equations:

x' = x - 4, y' = y -3

I recall answering this yesterday. Is it a repeat post?

For the three new vertex coordinates (x',y'), subtract 4 from the x values and 3 from the y values of the first three pairs of coordinates.

To find the new coordinates of each vertex after translation, we need to apply the given translations to the original coordinates of each vertex.

Let's apply the translation equations to get the new coordinates:

For vertex A:
x' = x - 4
y' = y - 3
x' = 0 - 4 = -4
y' = 6 - 3 = 3
Therefore, the new coordinates of vertex A after translation are A' = (-4, 3).

For vertex B:
x' = x - 4
y' = y - 3
x' = -2 - 4 = -6
y' = 3 - 3 = 0
Therefore, the new coordinates of vertex B after translation are B' = (-6, 0).

For vertex C:
x' = x - 4
y' = y - 3
x' = 2 - 4 = -2
y' = 1 - 3 = -2
Therefore, the new coordinates of vertex C after translation are C' = (-2, -2).

Hence, the coordinates of the vertices of the triangle ABC after translation by the equations x' = x - 4 and y' = y - 3 are A' = (-4, 3), B' = (-6, 0), and C' = (-2, -2).