A 1.80-cm-thick wood floor covers a 4.0 m times 5.5 m room. The subfloor on which the flooring sits is at a temperature of 16.1C, while the air in the room is at 19.2 C. What is the rate of heat conduction through the floor? Use 0.200 W/m* K for the thermal conductivity of wood.

i think we use P=K*A*DeltaT/L, right?
plz help

Yes, your formula is correct.

Heat loss rate = Q = (delta T)*area*(thermal conductivity)/(thickness)

=(3.1 K)(22 m^2)(0.200 W/m K)/0.018 m = __ W

Thank you!

Yes, you are correct! To find the rate of heat conduction through the wood floor, you can use the formula:

P = K * A * ΔT / L

Where:
P = rate of heat conduction (in watts)
K = thermal conductivity of wood (0.200 W/m*K in this case)
A = area (in square meters)
ΔT = temperature difference (in kelvin)
L = thickness of the wood floor (in meters)

In this case, the area A of the room is given as 4.0 m * 5.5 m = 22 m².

The temperature difference ΔT is calculated by subtracting the subfloor temperature from the air temperature:
ΔT = 19.2°C - 16.1°C = 3.1 K

Now we can substitute these values into the formula:

P = 0.200 W/m*K * 22 m² * 3.1 K / 1.80 cm

Note that we need to convert the thickness of the wood floor to meters by dividing it by 100:
L = 1.80 cm / 100 = 0.018 m

Now we can calculate the rate of heat conduction:

P = 0.200 W/m*K * 22 m² * 3.1 K / 0.018 m
P = 0.3007 kW

So, the rate of heat conduction through the wood floor is approximately 0.3007 kilowatts.

Yes, you are correct! To calculate the rate of heat conduction through the floor, you can use the formula:

P = K * A * ∆T / L

Where:
P is the rate of heat conduction (in watts),
K is the thermal conductivity of wood (0.200 W/m*K),
A is the area through which heat is being conducted (in square meters),
∆T is the temperature difference between the subfloor and the air (in Celsius), and
L is the thickness of the wood floor (in meters).

Now, let's plug in the values given in the question:
K = 0.200 W/m*K
A = 4.0 m * 5.5 m = 22.0 m² (since the room's dimensions are given as 4.0 m by 5.5 m)
∆T = 19.2°C - 16.1°C = 3.1°C
L = 1.80 cm = 0.018 m (since the thickness is given in cm)

Now we can substitute these values into the formula:

P = (0.200 W/m*K) * (22.0 m²) * (3.1°C) / (0.018 m)

P = 7.04 W

So, the rate of heat conduction through the wood floor is approximately 7.04 watts.