The volume of an ideal gas is 2.06L at standard temperature and pressure. Calculate the volume at 1.75 atm and 27 degrees celcius.

To calculate the volume of an ideal gas at a different pressure and temperature, we can use the Combined Gas Law equation:

(P₁ * V₁) / (T₁) = (P₂ * V₂) / (T₂)

Here,
P₁ = pressure at the initial state (STP) = 1 atm
V₁ = volume at the initial state = 2.06 L
T₁ = temperature at the initial state (STP) = 0 degrees Celsius or 273.15 K (converted to Kelvin)
P₂ = pressure at the final state = 1.75 atm
V₂ = volume at the final state (which we need to calculate)
T₂ = temperature at the final state = 27 degrees Celsius or 300.15 K (converted to Kelvin)

Substituting these values into the equation, we get:

(1 atm * 2.06 L) / (273.15 K) = (1.75 atm * V₂) / (300.15 K)

Now, we can solve for V₂:

V₂ = [(1 atm * 2.06 L) / (273.15 K)] * [(300.15 K) / (1.75 atm)]
V₂ = 2.444 L

Therefore, the volume of the ideal gas at 1.75 atm and 27 degrees Celsius is approximately 2.444 L.