chemistry

posted by .

When combined with cupric ions (aq, 1M) which will produce the largest standard cell voltage? (Use data from table 20.1, and Appendix D page A28-A29 in Petrucci)
1. ) Mn(s)
2. ) MnCl2(aq)
3. ) KMnO4(aq)
4. ) MnO2(s)

the answer i got was MnCl2,,,,but im not sure if its right...can someone confirm it?

  • chemistry -

    what is going to reduce Cu2+ ions then if all you have are Cl- ions (does not like being oxidized) and Mn2+ ions (wants to be reduced not oxidized)

  • chemistry -

    so would the answer be Mn (s)?

  • chemistry -

    lol

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chemistry

    When combined with cupric ions (aq, 1M) which will produce the largest standard cell voltage?
  2. chemistry

    how do you find the standard electrode potentials of KMnO4 and MnCl2?
  3. chemistry

    When combined with cupric ions (aq, 1M) which will produce the largest standard cell voltage?
  4. chemistry

    When combined with cupric ions (aq, 1M) which will produce the largest standard cell voltage?
  5. Chemisrty

    Chlorine gas can be produced in the laboratory by adding concentrated hydrochloric acid to manganese(IV) oxide in the following reaction.. MnO2(s)+ 4HCl(aq)-->MnCl2(aq)+ 2H2O(l)+ Cl2(g) A. Calculate the mass of MnO2 needed to produce …
  6. CHEM HELPP!

    Chlorine gas can be produced in the laboratory by adding concentrated hydrochloric acid to manganese(IV) oxide in the following reaction.. MnO2(s)+ 4HCl(aq)-->MnCl2(aq)+ 2H2O(l)+ Cl2(g) A. Calculate the mass of MnO2 needed to produce …
  7. Chemistry

    Consider the reaction MnO2+4HCL===>MnCl2+Cl2+2H2O How many grams of MnO2 are required to produce 5.6 of Cl2 at stp?
  8. chemistry

    MnO2+4HCl-->MnCl2+2H20+Cl2 a. calculate the mass of MnO2 needed to produce 25 g of Cl2 b. what mass of MnCl2 is produced when 0.091 g of Cl2 is generated?
  9. Chemistry

    In a dry cell, MnO2 occurs in a semisolid electrolyte paste and is reduced at the cathode. The MnO2 used in dry cells can itself be produced by an electrochemical process of which one half-reaction is shown below. Mn2+(aq) + 2 H2O(l) …
  10. chemistry

    In a dry cell, MnO2 occurs in a semisolid electrolyte paste and is reduced at the cathode. The MnO2 used in dry cells can itself be produced by an electrochemical process of which one half-reaction is shown below. Mn2+(aq) + 2 H2O(l) …

More Similar Questions