The 93 nature camp students ate lunch at the lodge. They sat at an even number of tables. There were 5 students sitting at one table, and an equal number of students sitting at each of the other tables. How many students were sitting at each of the other tables?
Solve by eliminating possibilities. You have to distribute 88 students equally among an even number of tables. There could be 44 tables with 2 each, or 22 with 4 each, or 11 with 8 each, or 8 with 11 each, etc. One choice is more likely (22 with 4) because that is a more reasonable table size.
There is several possible solutions, and for that reason this is not a very good question for teaching math.
this question had alot of possible answers and to a 9/10 yr old kid that can be very confusing therefore this question is terrible
To find the number of students sitting at each of the other tables, we need to take the total number of students and subtract the 5 students sitting at one table.
Given that there were 93 nature camp students, we can subtract 5 from 93 to find out how many students were left to be distributed among the other tables.
93 - 5 = 88
So, there were 88 students left to be seated at the other tables.
We know that an equal number of students were sitting at each of the other tables. Let's call this number "x."
This means that the remaining 88 students were divided into several tables, with each table having an equal number, which is x.
To find out how many students were sitting at each of the other tables, we can divide the remaining number of students (88) by the number of tables.
Let's say there were t other tables. So, we have the equation:
88 รท t = x
To solve for x, we need to know the number of tables. Unfortunately, the question doesn't provide that information.
To find the specific number of students sitting at each of the other tables, we need to know the total number of tables.