The titration of a sample of a weak acid with an equivalent weight of 108 grams requires 38.2 mL of 0.100 M NaOH. What is the sample mass in mg?
mL x N x milliequivalent weight = grams.
To find the mass of the sample in milligrams, we need to use the equation:
Mass (in mg) = (Volume of NaOH solution, in mL) × (Molarity of NaOH, in mol/L) × (Equivalent weight of weak acid, in g/mol)
Let's plug in the given values into this equation:
Volume of NaOH solution = 38.2 mL
Molarity of NaOH = 0.100 mol/L
Equivalent weight of weak acid = 108 g/mol
Mass (in mg) = (38.2 mL) × (0.100 mol/L) × (108 g/mol)
Now, let's calculate the final answer:
Mass (in mg) = 412.56 mg
Therefore, the mass of the sample is 412.56 mg.