A metal stays solid at Fahrenheit temp below 1868.5

Determine (in terms of an inequality) those Celsisu temp, for which the metal stays solid. Use the formula

F=9/5c+32

1868.5 = (9/5)c + 32

multiply by 5
9342.5 = 9c + 160

solve for c

then change to inequality

cIc<1020.28

Thanks!

To determine the Celsius temperature for which the metal stays solid, we can use the formula F = (9/5)C + 32, where F is the Fahrenheit temperature and C is the Celsius temperature.

Given that the metal stays solid at Fahrenheit temperatures below 1868.5, we can set up the following inequality:

F < 1868.5

Substituting F with the formula (9/5)C + 32, we get:

(9/5)C + 32 < 1868.5

To isolate C, we can start by subtracting 32 from both sides of the inequality:

(9/5)C < 1868.5 - 32
(9/5)C < 1836.5

Then, to solve for C, we can multiply both sides of the inequality by 5/9:

C < (1836.5)(5/9)
C < 1019.166...

So, in terms of an inequality, the Celsius temperature for which the metal stays solid can be expressed as:

C < 1019.166...

To determine the Celsius temperature for which the metal stays solid, we can use the given formula to relate Fahrenheit and Celsius temperatures:

F = (9/5)C + 32

Since we want to find the Celsius temperature range for which the metal stays solid, we need to rearrange the formula to solve for C:

C = (5/9)(F - 32)

Now we can substitute the given condition that the metal stays solid below 1868.5 Fahrenheit into our formula:

C = (5/9)(1868.5 - 32)

Simplifying further:

C = (5/9)(1836.5)

C ≈ 1020.2778

Therefore, the inequality representing the Celsius temperatures for which the metal stays solid is:

C ≤ 1020.2778