Please help me find the AXIS OF SYMMETRY for this...
y= -5xsquared-10x
To find the axis of symmetry for a quadratic equation in the form of y = ax^2 + bx + c, you can use the formula x = -b / (2a).
In your equation y = -5x^2 - 10x, we can see that a = -5 and b = -10.
Now, substitute these values into the formula x = -b / (2a):
x = -(-10) / (2 * -5)
x = 10 / -10
x = -1
Therefore, the axis of symmetry for the given quadratic equation is x = -1.