x+3y=-10
7x-5y=34
solve using substitution method
x+3y=-10 ......(1)
7x-5y=34 ......(2)
From (1), write it as:
x=-10-3y ......(3)
Substitute x in (3) into (2)
7(-10-3y)-5y=34 .....(4)
Expand the left hand side
-70-21y-5y=34
Isolate y
-21y-5y = 34 + 70
-26y = 104
Calculate y:
y=104/-26 = -4 .....(5)
Now substitute (5) into (3) to find x.
After that, substitute the values of x and y into equations (1) and (2) to verify if the solutions are correct.
x=-3y-10
7(-3y-10)-5y=34
-21y-70-5y=34
-27y-70=34
-21y=104
y=-104/21
this is your y value now just plug this value back into the x to find your x value
hope this helped.
this is wrong
To solve this system of linear equations using the substitution method, you can follow these steps:
Step 1: Solve one equation for one variable in terms of the other variable.
Let's solve the first equation, x + 3y = -10, for x:
x = -10 - 3y
Step 2: Substitute the expression for x into the second equation.
Replace x in the second equation with (-10 - 3y):
7(-10 - 3y) - 5y = 34
Step 3: Simplify and solve for y.
Distribute 7 to (-10 - 3y):
-70 - 21y - 5y = 34
Combine like terms on the left side:
-26y - 70 = 34
Add 70 to both sides:
-26y = 104
Divide both sides by -26:
y = -4
Step 4: Substitute the value of y back into one of the original equations to solve for x.
Let's use the first equation, x + 3y = -10:
x + 3(-4) = -10
x - 12 = -10
Add 12 to both sides:
x = 2
Step 5: Check your solution.
Substitute the values of x and y back into both original equations:
Equation 1: 2 + 3(-4) = -10
Equation 2: 7(2) - 5(-4) = 34
If both equations are true, then your solution is correct. In this case, the values of x = 2 and y = -4 satisfy both equations, so the solution to the system of equations is x = 2 and y = -4.