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physics

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A stone is dropped into a river from a bridge 41.7 m above the water. Another stone is thrown vertically down 1.87 s after the first is dropped. Both stones strike the water at the same time. What is the initial speed of the second stone?

  • physics -

    S=ut-(1/2)gt²
    S=41.7 m, u=0, g=9.8 m/s²
    Solve for t.
    Now
    S=v0(t-1.87) - (1/2)g(t-1.87)²
    Solve for v0.

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