A 2.7 kg box is released on a horizontal surface with an initial speed of 2.9 m/s. It moves on the surface with an acceleration of .27 m/s squared. Calculate the kinetic friction force on the box. The coefficent of the kinetic force is .156.
The acceleration is negative since the surface is horizontal and friction is the only horizontal force acting.
Compute the friction force from
F = m a
That gives F = 0.73 Newtons
There is another way to compute the friction force, and it gives a different result.
F = (kinetic coefficient) * M g
Your problem is inconsistent and overspecified. The initial speed makes no difference.
To calculate the kinetic friction force on the box, we can use the equation:
Kinetic friction force = coefficient of kinetic friction * normal force
In this case, the normal force is equal to the weight of the box, which can be calculated using the formula:
Normal force = mass * gravitational acceleration
The mass of the box is given as 2.7 kg, and the gravitational acceleration is approximately 9.8 m/s^2.
Normal force = 2.7 kg * 9.8 m/s^2
Now, let's calculate the normal force:
Normal force = 26.46 N
Next, we can calculate the kinetic friction force using the formula:
Kinetic friction force = coefficient of kinetic friction * normal force
The coefficient of kinetic friction is given as 0.156.
Kinetic friction force = 0.156 * 26.46 N
Finally, let's calculate the kinetic friction force:
Kinetic friction force = 4.11816 N
Therefore, the kinetic friction force acting on the box is approximately 4.12 N.