ALGEBRA
posted by BELLA .
I know the answers, but am having trouble writing the equation. Their ages are 17 and 8.5, and 14.5
Can I get help with the equaiton?
The sum of the ages of Sonia, Collin, and Ana is 40. Sonia is twice as old as Ana. Ana is 6 years younger than Collin. How old are they? Write and solve an algebra equation.(may have decimals)

It's odd, most of the time, questions regarding ages are integer numbers. I agree with your answer, here's how you could have done it.
Let A,S, and C represent the age of each person.
The sum of the ages of Sonia, Collin, and Ana is 40, so
S+C+A=40......(1)
Sonia is twice as old as Ana, so
S=2A.......(2)
Ana is 6 years younger than Collin, so
C=A+6......(3)
Notice how S and C both have been expressed in terms of A.
Now substitute (2) and (3) in (1) to get
S+C+A=40
(2A)+(A+6)+A = 40
4A+6=40
4A=34
A=8.5
The rest is just substituting A=8.5 in equations (2) and (3).
Hope that helps.
Respond to this Question
Similar Questions

algebra
The present ages in years of four cousins are consecutive multiples of 3. Five years ago the sum of their ages was 46. What is their ages now? 
algebra
brian is 26 years older than his daughter kim. the sum of their ages is twice the differences of their ages. find their ages. 
Algebra
Brian is 26 years oldr than his daughter Kim. The sum of their ages is twice the differences of their ages. Find theri ages. 
Math
My median answer is 19 for the ages of houses. How do I explain this represents the ages of the houses best? 
Math
The sum of the ages of a woman and her daughter is 46years.In 4 years, the ratio of their ages will be 7:2. Find their present ages. 
Math
The sum of the ages of a woman and her daughter is 46years.In 4 years, the ratio of their ages will be 7:2. Find their present ages. 
math
Richard is 6 years older than Lisa, and in 5 years the sum of their ages will be twice as much as the sum of their ages 4 years ago. Find their present ages. 
math
Richard is 6 years older than Lisa, and in 5 years the sum of their ages will be twice as much as the sum of their ages 4 years ago. Find their present ages. 
PreAlgebra
The sum of their ages. is 97. The difference of their ages is 19. Find their ages. 
algebra
the sum of ages of maria and anna is 35. when maria was twothirds her present age and anna was three fourths of her present ages, the sum of their ages was 25. how old is maria now?