College Math II

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If a ball is tossed into the air from a height of 6 feet
with a velocity of 32 feet per second, then its altitude at time t (in seconds)
can be described by the function

A(t) = - 16t^2 + 32t + 6.

Find the altitude of the ball at 2 seconds.
I am having problems understanding how to work out this word solving problem. Can someone help me? Thanks.

  • College Math II -

    Well if you're given the equation, the variable you need is "t" in order to solve the equation so if you just plug in 2 for "t" then you get your A(t). Just plug in A(t) = -16(2^2) + 32(2) +6

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