I am stumped...please help...I'm not sure what they are talking about with P (A and B) = 0
If P(A) = 2/3, P(B) = 1/6, and P(A and B) = 0, what can you say about P (A or B)?
The probability of all events occurring is found by multiplying the probability of the individual events.
2/3 * 1/6 = 2/18 = 1/9
So, with the information above, I don't know how P(A and B) could equal 0.
The either-or probability is found by adding the individual probabilities.
2/3 + 1/6 = 4/6 + 1/6 = 5/6
I hope this helps. If not repost your question(s) in more detail.